Two circular loops are parallel, coaxial, and almost in contact, with their cent

Question

Two circular loops are parallel, coaxial, and almost in contact, with their centers 0.85 mm apart (see figure below). Each loop is 8.0 cm in radius. The top loop carries a clockwise current of I-136 A. The bottom loop carries a counterclockwise current of I- 136 A. (a) Calculate the magnetic force exerted by the bottom loop on the top loop. magnitude directionSelect (b) Suppose a student thinks the first step in solving part (a) is to use B,- 2-2)372 to find the magnetic field created by one of the loops. How would you 2 a + argue for or against this idea? (c) The upper loop has a mass of 0.021 0 kg. Calculate its acceleration, assuming the only forces acting on it are the force in part (a) and the gravitational force magnitude directionSelect- m/s2

Explanation / Answer

Given,

Current, I = 136 A

Radius, r = 8 cm

Force between the loops = u0*i1*i2*l/(2*pi*d)

F = (4 pi*10^-7) * 136 * 136 * (2*pi*0.08) /(2*pi*0.00085)

F = 2.188 N

So, magnetic force on the upper loop is 2.188 N (upwards)

b)

Fnet = Fm - mg

Fnet = 2.188 - 0.021 * 9.8

Fnet = 1.98 N

Using second law of motion

a = Fnet/m

a = 1.98/ 0.021 = 94.37 m/s^2

So, the acceleration of the upper loop is 94.37 m/s^2

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