Experimental Objectives The rotating platform used in this experiment is shown i

Question

Experimental Objectives The rotating platform used in this experiment is shown in Figure 2. There is a spring on the central rotation axis of the system which provides the force required to keep the brass bob in uniform circular motion. You can adjust the spring length and the position of the bob. The position of the bob during rotation can be monitored with the orange marker/indicator as it aligns with the reference slot. The platform is connected to the computer interface through a rotational motion sensor. You will be able to record the angular velocity of the rotation using the computer interface. Your TA will explain how to operate the platform and collect data with the Data Studio software. Besides the platform, you will need a set of different hanging weights. spring bob removable balancing mass rotating platform Figure 2: The rotating platform .Devise an experimental procedure to verify that the accelerating force is proportional to the square of the angular velocity of rotation. Hint: Do not spin the rotating platform with the hanging mass attached. Make a plot of F vs. w2 and explain the slope in your lab report. Devise an experimental procedure to verify that the force that keeps the bob in uniform circular motion is proportional to the radius of the rotation

Explanation / Answer

Answer:-a) The plane wave Ez = 3ax + 4ay is linearly polarized with angle of, angle = tan-1(4/3) = 53.130 .

b) The total electric field can be witten as Ez = (3ax + 4ay)e-jk0z in phasor form, where k0 is the wave number. But the magnetic field equation from electric field equation can be written as Hz = Ez / intrinsic impedance of dielectric. But intrinsic impedance is inversly proportional to the square root of dielectric constant. So overall,

Hz = [(3ax + 4ay) x (11.9)0.5 / 377]e-jk0z A/m. Note 377 ohm is intrinsic impedance of air.

c) Ez = 3ax + 4ay from this magnitude of Ez = 5 V/m. So for equal division among x and y axis we can use amplitude of 5/(2)0.5 = 3.53 V/m.

Now a wave in the form Ez = E0 (x + jy)e-jk0z gives wave in left-hand circularly polarized form(LHCP).

For RHCP, Ez = E0 (x - jy)e-jk0z .

Hence for RHCP Ez = 3.53 (x - jy)e-jk0z and for LHCP Ez = 3.53 (x + jy)e-jk0z   .

d) Both RHCP and LHCP have same amplitude.

e) phase difference is always 900 .

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