An object has a weight of 400 N when it is dry. When it is completely submerged

Question

An object has a weight of 400 N when it is dry. When it is completely submerged in water is has a weight of 150 N. What is the density of the material is the density of water is 1000 kg/m3?

a. 2300 kg/m3

c. 1200 kg/m3

d. 1600 kg/m3

b. 4500 kg/m3

QUESTION 2

If a car horn honking that is 450 m is heard 1.3 seconds after it goes off, what is the temperature in degrees Celsius?

b. 34 °C

d. 12 °C

c. 56 °C

a. 25 °C

QUESTION 3

Using the standard form of a wave x = A cos(?t), for this wave: 2.5 cos(6.0 t) please determine the following with the correct units:

a. The amplitude.

b. The frequency.

c. The maximum and minimum speed

d. The maximum acceleration

QUESTION 4

A piece of gold with a mass of 5.50 kg and density of 19300 kg/m3 is suspended from a string and then totally immersed in a beaker of water. Using density of water is 1000 kg/m3

a) Determine the volume of the piece of gold.

b) Determine buoyant force on the gold when it is submersed.

QUESTION 5

A 0.300 kg piece of metal is heated to 88°C and placed in a copper calorimeter with mass 0.150 kg which contains 0.500 L of water that are both initially at 12.6°C. Over a short period of time the mixture comes to an equilibrium temperature of 22.5°C, what is the specific heat of the metal?

b. 1500 J/(kg ? °C)

a. 1084 J/(kg ? °C)

c. 3400 J/(kg ? °C)

d. 1250 J/(kg ? °C)

  QUESTION 6

A gas is taken through the cycle illustrated here. During one cycle, how much work is done by an engine operating on this cycle?

3PV

4PV

PV

2PV

QUESTION 7

A CD with a diameter of 12.5 cm goes from rest to a tangential velocity of 5.6 m/s. If it does this in 2.5 seconds, what is its angular acceleration?

24 rad/s2

36 rad/s2

18 rad/s2

16 rad/s2

QUESTION 8

4.50 moles of an ideal gas is at 560K. Is the gas undergoes an adiabatic compression and 3750 J of work is done on the gas, what is the final temperature of the gas?

a. 627 K

c. 2590 K

d. 977 K

b. 572 K

A.

a. 2300 kg/m3

B.

c. 1200 kg/m3

C.

d. 1600 kg/m3

D.

b. 4500 kg/m3

Explanation / Answer

QUESTION 1

Buoyant force Fb = 400-150 = 250 N
x = Weight/Fb = 400/250 = 8/5 = 1.6 kg/dm^3 = 1600 kg/m^3

QUESTION 2

Vs = 331.4+0.6Tcelcius m/sec

Vs = 450/1.3 = 346.1m/s

346.1 - 331.4 = 14.8

therefore 14.8 = .6t
t = 24.6 degrees celSius

QUESTION 3

a) Amplitude = 2.5 m

b)Frequency, f = 6/ 2*pi = 0.955 Hz

c) Maximum speed, V = Aw = 2.5*6 = 15 m/s, Minimum Speed = zero m/s

d) Maximum acceleration = Aw^2 = 2.5*36 = 90 m/s2

QUESTION 4

a)

volume V = 5.5/19.3 = 0.2850 dm^3

b)

buoyant force = V* = 0.2850*9.8 = 2.79275 N

QUESTION 5

The heat given by the metal and calorimeter = The heat taken by water

c(Metal)m(metal)(Ti1Tf)+c(copper)m(calorimeter)(Ti1Tf)=m(water)C(water)(TfTi2)

C(copper)=385J/(kgK)

Cwater=4811J/(kgK)

C(Metal)*0.3*(88-22.5) = 385*0.15*(22.5-12.6) +0.5*4811*(22.5-12.6)

19.65*c(metal) =571.725 +23814.45

c(metal)=1241.02J/(kgK)

Correct answer is D) 1250 J/kg/K

QUESTION 6

Work done is w =PdV, we need to know the pressure, initial and final volumes, substitute, then we obtain the workdone

QUESTION 7

Angular velocity =V/R=5.6/0.125=44.8rad/sec

angular acceleration =/t=44.8/2.5=17.92rad/s2

Correct answer is C) 18 rad/s^2

QUESTION 8

Adiabatic compression it means there is no heat exchanged.

variation of internal energy = work done

(U)=Work

NCv(TfTi)=3750
where N is the number of gas moles, Cv=(3/2)R=12.5J/(molK)
4.512.5(Tf560)=3750
Tf560=66.67

Tf=626.67K

Correct answer is A) 627 K

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.