Hi all I think I\'ve some how managed to confuse myself I gotthat u 2 \'= -1/3(x

Question

Hi all I think I've some how managed to confuse myself I gotthat u2'=-1/3(x+1)e^x buthow does that became u2=-1/3xe^x I'm gettingu2=-1/3(2e^x+xe^x) or-1/3(2+x)e^x I'm guess that one of mye^x should of became a negative to cancel thee^x and just leave you withu2=-1/3xe^x but how? thanks very much foryour help Hi all I think I've some how managed to confuse myself I gotthat u2'=-1/3(x+1)e^x buthow does that became u2=-1/3xe^x I'm gettingu2=-1/3(2e^x+xe^x) or-1/3(2+x)e^x I'm guess that one of mye^x should of became a negative to cancel thee^x and just leave you withu2=-1/3xe^x but how? thanks very much foryour help I'm gettingu2=-1/3(2e^x+xe^x) or-1/3(2+x)e^x I'm guess that one of mye^x should of became a negative to cancel thee^x and just leave you withu2=-1/3xe^x but how? thanks very much foryour help

Explanation / Answer

Hi all I think I've some how managed to confuse myself I gotthat u2'=-1/3(x+1)e^x buthow does that became u2=-1/3xe^x I'm gettingu2=-1/3(2e^x+xe^x) or-1/3(2+x)e^x I'm guess that one of mye^x should of became a negative to cancel thee^x and just leave you withu2=-1/3xe^x but how? thanks very much foryour help
   u = -1/3 int (x+1)ex dx using partialintegral
          u = x +1             dv = ex dx
        du =dx                    v = ex
       = -1/3 { (x+1)ex -int ex dx)}
       = -1/3 { xex + ex -ex) = -1/3 xex
I'm gettingu2=-1/3(2e^x+xe^x) or-1/3(2+x)e^x I'm guess that one of mye^x should of became a negative to cancel thee^x and just leave you withu2=-1/3xe^x but how? thanks very much foryour help
   u = -1/3 int (x+1)ex dx using partialintegral
          u = x +1             dv = ex dx
        du =dx                    v = ex
       = -1/3 { (x+1)ex -int ex dx)}
       = -1/3 { xex + ex -ex) = -1/3 xex

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