2. Suppose that snowfall in Indiana follows an exponentialdistribution with mean
ID: 2954364 • Letter: 2
Question
2. Suppose that snowfall in Indiana follows an exponentialdistribution with mean 15 inches per winter season.
(a) Find the probability that the snowfall will exceed 17 inchesin a specific winter.
(b) Find the probability that in four out of the next fivewinters the snowfall will be less than the mean.
3. Sales in a fast food restaurant are normally distributed withmean $42,000 and standard deviation $2,000 during a salesperiod. During a recent sales period, sales were reported toa local taxing authority to be $37,600. Should the taxingauthority be suspicious?
Explanation / Answer
a) this probability can be found using the complement of 17 orfewer inches falling (poissoncdf(15,17)=.7489. 1-that value willgive us the probability of more than 17 inches. 1-.7489 is .2511,or about 25.1% b)Assuming that each winter is independent, the probability ofthe winter being less than 15 inches is poissoncdf(15,15)=.568.Now, we can use the binomial distribution to find the probabilityof 4 out of 5 winters having less than that... binompdf(5,.568,4)=.2249, or about 22.5% c) the z-score for 37,600 is (37600-42000)/2000=-2.2 Theprobability of seeing that z-score or lower isnormcdf(-1000000000,-2.2)=.0139 or about 1.39%. I would be a little suspicious; that seemspretty low. c) the z-score for 37,600 is (37600-42000)/2000=-2.2 Theprobability of seeing that z-score or lower isnormcdf(-1000000000,-2.2)=.0139 or about 1.39%. I would be a little suspicious; that seemspretty low.Related Questions
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