please ansewr these questions... will rate u 5 stars A steam power plant schemat
ID: 2994947 • Letter: P
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please ansewr these questions...
will rate u 5 stars
A steam power plant schematic is shown in the figure, it operates at steady state with mass flow rate of 50 kg/sec ke and pe changes throughout the cycle is negligible. Properties of various states are given below. 250 bars and 400 degree c (superheated h1 = 3254.9 kl/kg degree sat, liquid, 0.2 bar 250 bars and 80 degree c (h4 = 355 kl/kg ) sketch the cycle on a t-v or t-s diagram. Clearly mark the states and processes 1-2, determine work done by the turbine determine the heat loss by the condenser determine the work provided to the pump determine the heat gain by the boiler determine the cycle efficiency determine maximum cycle efficiency determine whether cycle is reversible, irreversible, or impossible-give reasons for your choice a power cycle receives energy qh = 500 kj by hot reservoir at the = 1500 degree k and rejects energy qc = 300kj by cold reservoir at tc = 900 degree k. determine whether this cycle operates reversibly, operates irreversibly, or is impossible a tank contains 0.06 m3 of argon at (-100 degree c) and 30 bars considering argon as compressible (non-ideal) gas, determine the mass of the gas in kg 1 kg/sec of compressed water enters an un-insulated valve at 250 bar and 80 degree c (ht = 355 kj/kg) operating at steady state, the water exits the valve at a pressure of 0.04 bar and velocity of 50 m/sec. the inlet velocity is negligible. Neglect the potential energy effects; determine the specific volume of water at the valve exist (state 2) draw the process on any diagramExplanation / Answer
a . carnot efficiency =1-900/1500 = 0.4
also cycle efficiency =(500-300)/500 =0.4
hence as these 2 efficiencies are same .. cycle is operated revercibly
... b pv=nrt
mass of argon is 40
0.06 m^3 =6 lits
r = 0.0831 for given units
30*60 =(m/40) *173*0.0831
hence m =5008 gm =5.008 kg
..........
c mass flow rate will remain same
1kg/sec =rho *v A
hence rho =1/50
specific volume =1/ rho hence =50
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