Glucose labeled with 14C in C-3 and C-4 is completely converted to acetyl-CoA vi

Question

Glucose labeled with 14C in C-3 and C-4 is completely converted to acetyl-CoA via glycolysis and the pyruvate dehydrogenase complex. What percentage of the acetyl-CoA molecules formed will be labeled with 14C, and in which position of the acetyl moiety will the 14c label be found? a) 100% of the acetyl-CoA will be labeled at C-1 (carboxyl). b) 100% of the acetyl-CoA will be labeled at C-2 c) 50% of the acetyl-CoAwill be labeled, all at C-2 (methyl). d) No label will be found in the acetyl-CoA molecule d1/21/2018

Explanation / Answer

Option (b) is correct

100% of the Acetyl CoA will be labeled at C-2

Reason - glucose 1st turns into pyruvic acid and only c-3 takes part in pyruvic acid formation. After that pyruvic acid turns into Acetyl- coA and in this procees C-3 of pyruvic acid changed in C-2 of Acetyl-coA. So all Acetyl-coA will be lebeled at C-2(methyl).

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