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Chapter 29 - Protected View - Saved to this PC Slide Show Review View Help Story

ID: 306161 • Letter: C

Question

Chapter 29 - Protected View - Saved to this PC Slide Show Review View Help Storyboarding Tell me what you want to do ou need to edit, it's safer to stay in Protected View. Enable Editing Ch. 29: Magnetic Fields of Currents G. Assignments Find the force between two parallel currents of 5 A and 10 A, each two meters long with distance of 2 cm. At the middle of the two currents, what is the magnetic field? 1. 2. A 200-turn solenoid with length of 20 cm and diameter of 2 cm. When a 5-A current passes through the solenoid, find the magnetic field within the solenoid.

Explanation / Answer

here,

1)

I1 = 5 A

I2 = 10 A

length of wire , l = 2 m

sepration , r = 2 cm = 0.02 m

the force between the wires , F = u0 * I1 * I2 * l /(2 *pi*r)

F = 1.26 * 10^-6 * 5 * 10 * 2 /( 2 *pi*0.02) N

F = 1 * 10^-3 N

the magnetic feild , B = u0 * l/(2*pi*(r/2)) * ( I2- I1)

B = 1.26 * 10^-6 * 2 /( pi * 0.02) * ( 10 - 5) T

B = 2 * 10^-4 T

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