Calculate the probability of the “Motor fails to operate” event. Assume the prob
ID: 3070362 • Letter: C
Question
Calculate the probability of the “Motor fails to operate” event. Assume the probability of occurrence of all basic (circle) events is equal to 0.01 and the probability of the event “Switch opened erroneously” is equal to 0.005. Assume that the condition “Fuse fails open” has a probability of occurrence of 0.90. OR gates = P(A) + P(B);
Motor fails to operate Defect in motor No current to motor 2 Wire failure (open) Power Fuse fails open Switch Fuse failure under Switch Fuse failure due to overload (open) Fuse fails 5 in circuit Wire failure (shorted) Power failure (surge)Explanation / Answer
Probability of Overload in circuit = Probability of Wire Failure + Probability of Power failure = 0.01 + 0.01 = 0.02
Probability of fuse failure due to overload = Probability of overload * Probability of fuse fails to open = 0.02 * 0.90 = 0.018
Probability of fuse fails open = Probability of fuse failure due to overload + Probability of fuse failure under normal conditions = 0.018 + 0.01 = 0.028
Probability of switch open = Probability of switch fails open + Probability of switch opened erroneously
= 0.01 + 0.005 = 0.015
Probability of no current to motor = Probability of switch open + Probability of wire failure + Probability of fuse fails open + Probability of power supply failure = 0.015 + 0.01 + 0.028 + 0.01 = 0.063
Probability of motor fails to operate = Probability of defect in motor + Probability of no current to motor = 0.01 + 0.063 = 0.073
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