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The graph shows the ideal gas law relationship (PV = nRT) between pressure (P) a

ID: 3111279 • Letter: T

Question

The graph shows the ideal gas law relationship (PV = nRT) between pressure (P) and volume (V). If the tank is at a temperature of 209 kelvin and is filled with nitrogen (formula, N_2: molecular weight, 28 grams per mole), what is the mass of gas in the tank (m) in units of grams? Click the icon to view the graph of the ideal gas law relationship. Click the icon to view the value and units of gas constant R for Ideal Gas Law. The mass of gas in the tank is grams. (Round your answer to three significant digits as needed.)

Explanation / Answer

Sol:

According to Ideal Gas Law PV = n RT

We need to find mass of the gass,

i,e

Mass = n * molar mass of N2

First we find n,

PV = n RT

n = PV / RT

From graph we have V = 10 P-1 [L atm] => V = 10 [L atm] / P => PV =10 [L atm]

Given that Temaparature T= 209 Kelvin , i,e T = 209 K

And R = 0.08206 [atm L] / (mole K)

n = PV / RT

= 10 [L atm] /( (0.08206 [atm L] / (mole K) ) 209 K)

= 10 / (0.08206 *209 ) mole

= 0.583072 mole

Now, finding mass

Mass = n * molar mass of N2

= 0.583072 mole * 28 gram / mole

= 16.3260 grams

= 16.326 grams ( three significant digit)

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