Suppose you are playing Poker alone. You have four cards (3, 4, 5, and 6). You a

Question

Suppose you are playing Poker alone. You have four cards (3, 4, 5, and 6). You are about to select one more card from the remaining deck. What is the probability that you get a straight flush (5 consecutive cards of the same suit)? Enter your answer in decimal form rounded to the 3rd decimal place.

I figured out that its an conditional probability. I broke this problem down to a straight and flush, but I'm having trouble getting a straight flush. (THIS IS A DIFFERENT SENARIO BUT IT IS A SIMILAR PROBLEM)

Straight: 48 cards left but only 9 hearts left (because I have 4 of them) Therefore P() = 9/48 = 0.1875 = 0.188

Flush: 48 cards left and would be happy with a 2 or a 7 of any suit. since there are four 2's and four 7's left in the deck, there are 8 ways for me to get what i want. P(straight) = 8/48 = 0.167

Straight flush: ?????????

Explanation / Answer

No. Since you have already 3 , 4,5,6 haerts, for a straight flush you required either 2 heart or 7 heart. So only two ways.

So probability is 2/48 = 0.042

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.