Suppose you are playing \"Let\'s Make a Deal\" (the Monte Hall game), but with f

Question

Suppose you are playing "Let's Make a Deal" (the Monte Hall game), but with four doors instead of three (there is still only one prize). You are told ahead of time that Door #1 is twice as likely as the others to be the winning door, so you select door #1. The host, who knows where the prize is, opens a door having no prize behind it. He asks if you'd like to change your door selection, should you? Justify your answer AND compute the final probability you win the prize (after you have taken your action or decided not to).

*NOTE: Fairly confident he should stick with door one, but unsure of probability.

Explanation / Answer

as probabilty behind door 1 to have prize=2/5=4/10

and probabilty of prize behind rest of 3 doors =3/5

as he oprns one door and there is no prize, probabilty that one door out of 2 other then door 1 will become (3/5)/2=3/10

as probabilty of having a prize behind door 1 is still higher then having a prize in any of the rest of two doors,

one should stick with door 1

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.