A study was conducted to determine the effectiveness of a certain treatment. A g

Question

A study was conducted to determine the effectiveness of a certain treatment. A group of 102 patients were randomly divided into an experimental group and a control group. The table shows the result for their net improvement. Let the experimental group be group 1 and the control group be group 2. Test whether the experimental group experienced a larger mean improvement than the control group at the alpha = 0.05 level of significance. Should the null hypothesis be rejected? Yes, because the test statistic is in the critical region. No, because the test statistic is not in the critical region. No, because the test statistic is in the critical region. Yes, because the test statistic is not in the critical region. Construct a 95% confidence interval about mu_1 - mu_2 and interpret the results. Therefore, the confidence interval is the range from to. (Round to two decimal places as needed.)

Explanation / Answer

t = ( 11.2 - 3.4 ) / ( srqt ( 6.4^2 / 61 + 6.6^2/ 41 ) ) t = 5.92 for alpha = 0.05 df=61+41-2=100 critical value : 1.64+ yes we should reject Ho because t> critical value 95% confidence interval alpha/2 = 0.025   Z=1.96 I: 11.2-3.4 +/- 1.96 * srqt [ (6.4^2/61) + 6.6^2/41 ] 7.8+/-2.58 5.22

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.