What arrangement of the three resistors, 2 Ohm, 3 Ohm, and 6 Ohm, yields an equi

Question

What arrangement of the three resistors, 2 Ohm, 3 Ohm, and 6 Ohm, yields an equivalent resistance of 4.5 Ohm? Draw a schematic figure. Two resistors (R_1 = 3 Ohm, R_2 = 6 Ohm) in parallel are connected to an emf epsilon = 1.5 V. How much current runs through R_1? A light bulb from another country rated at 100 W and 100 Volt is used in a lamp in the USA connected to a 120 Volt outlet. What is its power output? What is the terminal voltage of a battery whose emf is epsilon = 1.5 V and whose internal resistance is r = 0.5 Ohm when it is connected to a lightbulb whose resistance is R = 2.5 Ohm? The open circuit voltage of a source is 6 V, and its short circuit current is 6 A. What is the current when a resistance of 5 Ohm is connected across the terminals of the source?

Explanation / Answer

(2).2 ohm and 6 ohm are connected in parallel.

So, resultant resistance of these two is R then

(1/R) = (1/2) +(1/6)

R = ( 2x6) /(2+6)

= 12 / 8 = 1.5 ohm

R and 3 ohm are connected in series then equivalent resistance R ' = R + 3 ohm

R ' = 1.5 ohm + 3 ohm

= 4.5 ohm

(2). when two resistors are connected in parallel,then the potential difference is smae in both resistors.

So, potential difference in R1 is V = 1.5 volt.

Therefore Current through R1 is i = V / R1

= 1.5 /3 = 0.5 A

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