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Survey crews routinely work in off road areas where poison oak is common. Protec

ID: 3179334 • Letter: S

Question

Survey crews routinely work in off road areas where poison oak is common. Protective ointment A is routinely used to minimize the cases of poison oak among the survey crews. A new ointment, B, has been developed. We want conduct a hypothesis test to determine if the proportion of cases of poison oak using ointment A is more than the proportion of cases of poison oak using new ointment B. Two groups of survey crews are tested with ointment A and ointment B. The results are below. For each ointment, x is the number of cases of poison oak and n is the size of each sample using ointment A and ointment B. An appropriate null hypothesis is: A. P_A P_B C. P_A lessthanorequalto P_B D. P_A greaterthanorequalto P_B The p-value is A. 0.0327 B. 0.0667 C. 0.1014 D. can't calculate

Explanation / Answer

11) option C is correct

12) here pa =7/105 =0.067 ; na=105

pb=5/153=0.033 ; nb=153

hence std error =(pa(1-pa)/na+pb(1-pb)/nb))1/2 =0.028

hence test stat =(pa-pb)/std error =1.2022

for above test stat p value =0.1014

hence option C is correct