Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Consider a population that contains black and white cats where the black allele

ID: 322472 • Letter: C

Question

Consider a population that contains black and white cats where the black allele (B) is dominant and the white allele (b) is recessive. Indicate whether each statement is true or false.

1. Evolution is occurring in a population of cats where the genotype frequencies of BB, Bb, and bb are 0.64, 0.32, and 0.04, respectively.  TrueFalse
2. A population of cats is in Hardy-Weinberg equilibrium when the genotype frequencies of BB, Bb, bb are 0.49, 0.33, and 0.16, respectively.  TrueFalse
3. Evolution is occurring in a population of cats where the genotype frequencies of BB and Bb are 0.7 and 0.2, respectively.  TrueFalse
4. A population of cats is in Hardy-Weinberg equilibrium when the genotype frequencies of BB and Bb are 0.25 and 0.5, respectively TrueFalse

Explanation / Answer

Answer:

1). Flase

Hardy-Weinberg equilibrium= p^2 + 2pq+q^2=1

0.64+0.32+0.04=1 (not deviation from Hardy-Weinberg equilibrium)

2). False

Hardy-Weinberg equilibrium= p^2 + 2pq+q^2=1

0.49+0.33+0.16= 0.98 (deviation from Hardy-Weinberg equilibrium)

3). True

BB= 0.7

B = p=0.84

b= q= 0.16

bb= 0.03

Bb = 2pq= 2* 0.84 * 0.16= 0.27 (expected)

Hardy-Weinberg equilibrium= p^2 + 2pq+q^2=1

0.7+0.2 + 0.03= 0.93 (Deviation from Hardy-Weinberg equilibrium)

4). True

BB = 0.25

B= p=0.5

b=q=0.5

bb = 0.25

Bb = 2pq= 2 *0.5 * 0.5 = 0.5(expected)

Hardy-Weinberg equilibrium= p^2 + 2pq+q^2=1

0.25 + 0.5 + 0.25=1

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote