Consider a population that contains black and white cats where the black allele

Question

Consider a population that contains black and white cats where the black allele (B) is dominant and the white allele (b) is recessive. Indicate whether each statement is true or false. Evolution is occurring in a population of cats where the genotype frequencies of BB, Bb, and bb are 0.64, 0.32, and 0.04, respectively. True A population of cats is in Hardy-Weinberg equilibrium when the genotype frequencies of BB, Bb, bb are 0.49, 0.33, and 0.16, respectively. False Evolution is occurring in a population of cats where the genotype frequencies of BB and Bb are 0.7 and 0.2, respectively. _____ A population of cats is in Hardy-Weinberg equilibrium when the genotype frequencies of BB and Bb are 0.25 and 0.5, respectively. _____

Explanation / Answer

Answer:

1. False

Frequency of B = p2 + 1/2*2pq = 0.64 + 0.16 = 0.8

Frequency of b = q2 + 1/2*2pq = 0.04 + 0.16 = 0.2

So, p+q = 1, i.e, it follows HW equilibrium. So, the allele frequencies should remain constant.

2. True

Frequency of B = p2 + 1/2*2pq = 0.49 + 0.165 = 0.655

Frequency of b = q2 + 1/2*2pq = 0.16 + 0.165 = 0.325

So, p+q = 0.98, i.e, it doesnot follow HW equilibrium. So, evolutionary change is taking place.

3. True

Frequency of B = p2 + 1/2*2pq = 0.7 + 0.1 = 0.8

Frequency of b = q2 + 1/2*2pq = 0.1

So, p+q = 0.9, i.e, it doesnot follow HW equilibrium. So, evolutionary change is taking place.

4. True

Frequency of B = p2 + 1/2*2pq = 0.25 + 0.25 = 0.5

Frequency of b = q2 + 1/2*2pq = 0.25

So, p+q = 0.75, i.e, it doesnot follow HW equilibrium. So, evolutionary change is taking place.

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