You are given the following probabilities: P(A) = 0.55 P(B) = 0.40 P(A intersect

Question

You are given the following probabilities: P(A) = 0.55 P(B) = 0.40 P(A intersection B) = 0.36 Using the addition law, what is the probability of P(A union B)? (show your work) What is the conditional probability of A given B? (show your work) Using the multiplication law, calculate the probability of A intersection B. (show your work) If P(A) = .24 and P(B) = .3 and they are mutually exclusive, use the addition law to calculate P(A union B). (show your work) If P(A) = .34, what is the value of the compliment P(A^C)?

Explanation / Answer

21)P(AuB|=P(A)+P(B)-P(AnB)= 0.55+0.4-0.36=0.59

22)P(A|B)=P(AnB)/P(B)=0.36/0.4=0.9

23)P(AnB) =P(A)*P(B)=0.55*0.4=0.132

24)P(AUB)=0.24+0.3=0.54

25)P(Ac)=1-P(A)=1-0.34=0.66

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