A one-way ANOVA is used by the H.R. department to test the null hypothesis that
ID: 3237735 • Letter: A
Question
A one-way ANOVA is used by the H.R. department to test the null hypothesis that the means of three populations are all equal. The table below shows how 30 employees rated their training on a scale of 1-10.
A significance level of 0.05 is used.
Class Room
Job Shadowing
CBT
7
9
6
5
8
8
6
5
7
8
8
8
6
7
6
7
6
8
9
8
9
5
6
8
6
5
7
7
9
8
Anova: Single Factor
SUMMARY
Groups
Count
Sum
Average
Variance
Class Room
10
66
6.6
1.6
Job Shadowing
10
71
7.1
2.322222222
CBT
10
75
7.5
0.944444444
ANOVA
Source of Variation
SS
df
MS
F
P-value
F crit
Between Groups
4.067
2.000
2.033
1.253
0.302
3.354
Within Groups
43.8
27
1.622
Total
47.867
29
If F > F crit we reject the null hypothesis.
Results:
The ANOVA test results show that F < F crit therefore we do not reject the null hypothesis. The means of the three populations provided are equal.
Accept the null hypothesis that the three groups have equal means.
Are the results of the ANOVA application statistically significant? Why are the results significant or not significant? Explain your reasoning.
Class Room
Job Shadowing
CBT
7
9
6
5
8
8
6
5
7
8
8
8
6
7
6
7
6
8
9
8
9
5
6
8
6
5
7
7
9
8
Anova: Single Factor
SUMMARY
Groups
Count
Sum
Average
Variance
Class Room
10
66
6.6
1.6
Job Shadowing
10
71
7.1
2.322222222
CBT
10
75
7.5
0.944444444
Explanation / Answer
H0:all three group means are equal(claim)
H1:atleast one of the means are different
p=0.302
p>0.05
decision rule
p<0.05 reject null hypothesis
p>0.05 fail to reject null hypothesis
here p>0.05
Fail to reject null hypothesis
Accept null hypothesis.
Results are statistically significant.
there is sufficient evidence at 5% level of significance to conclude that means are SAME
ALL THREE GROUP MEANS ARE EQUAL
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