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A one-way ANOVA is used by the H.R. department to test the null hypothesis that

ID: 3237735 • Letter: A

Question

A one-way ANOVA is used by the H.R. department to test the null hypothesis that the means of three populations are all equal. The table below shows how 30 employees rated their training on a scale of 1-10.

A significance level of 0.05 is used.

Class Room

Job Shadowing

CBT

7

9

6

5

8

8

6

5

7

8

8

8

6

7

6

7

6

8

9

8

9

5

6

8

6

5

7

7

9

8

Anova: Single Factor

SUMMARY

Groups

Count

Sum

Average

Variance

Class Room

10

66

6.6

1.6

Job Shadowing

10

71

7.1

2.322222222

CBT

10

75

7.5

0.944444444

ANOVA

Source of Variation

SS

df

MS

F

P-value

F crit

Between Groups

4.067

2.000

2.033

1.253

0.302

3.354

Within Groups

43.8

27

1.622

Total

47.867

29

If F > F crit we reject the null hypothesis.

Results:

The ANOVA test results show that F < F crit therefore we do not reject the null hypothesis. The means of the three populations provided are equal.

Accept the null hypothesis that the three groups have equal means.

Are the results of the ANOVA application statistically significant? Why are the results significant or not significant? Explain your reasoning.

Class Room

Job Shadowing

CBT

7

9

6

5

8

8

6

5

7

8

8

8

6

7

6

7

6

8

9

8

9

5

6

8

6

5

7

7

9

8

Anova: Single Factor

SUMMARY

Groups

Count

Sum

Average

Variance

Class Room

10

66

6.6

1.6

Job Shadowing

10

71

7.1

2.322222222

CBT

10

75

7.5

0.944444444

Explanation / Answer

H0:all three group means are equal(claim)

H1:atleast one of the means are different

p=0.302

p>0.05

decision rule

p<0.05 reject null hypothesis

p>0.05 fail to reject null hypothesis

here p>0.05

Fail to reject null hypothesis

Accept null hypothesis.

Results are statistically significant.

there is sufficient evidence at 5% level of significance to conclude that means are SAME

ALL THREE GROUP MEANS ARE EQUAL

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