A 11.0 L vessel contains gas at a temperature of 0.00 C and a pressure of 3.00 a

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A 11.0 L vessel contains gas at a temperature of 0.00 C and a pressure of 3.00 atm. How many moles of gas are in the vessel? 1.5 mol How many molecules are in the vessel? 9 03e+23 molecules 1.11 points 1 Answers Tipler6 17 P 054 An automobile tire is filled to a gauge pressure of 175 kPa when its temperature is 2 the car has been driven at high speeds, the tire temperature increases to 51°C. pressure is the difference between the actual pressure and atmospheric pressure.) After 0°C. (Gauge that the volume of the tire does not change, and that air behaves as an ideal x kPa gas, find the gauge pressure of the air in the tire. 221.12 b) Calculate the gauge pressure if the volume of the tire expands by 10%. kPa Apply the ideal-gas law for a fixed amount of gas to relate the temperatures to the pressures of the air in the tire. elook y Notes Ask Your Teache 6. 11.11/11.11 points Previous Ansurers Tiplers 17 P 000 Find the total translational kinetic energy of 2.5 L of oxygen gas held at a temperature of oec and a pressure of 1i3 atm. 493 34 O Type here to search

Explanation / Answer

Here ,

part A) initial gaugre pressure , Pi = 175 kPa

initial absolute pressure = 175 + 101 = 286 kPa

T1 = 20 degree C = 293 K

T2 = 51 degree C = 324 K

Using ideal gas equation

P1/T1 = P2/T2

286/293 = P2/324

P2 = 316 kPa

gauge pressure = 316 - 101 = 215 kPa

the final gauge presure is 215 kPa

b) if the volume also increases by 10 percent

initial volume = V

final volume = 1.1 * V

Using ideal gas equation

P1* V1/T1 = P2 * V2/T2

286 * V /293 = P2 * 1.1 V/324

286 /293 = P2 * 1.1/324

P2 = 287.5 kPa

final gauge pressure = 287.5 - 101

final gauge pressure = 186.5 kPa

the final gauge pressure is 186.5 kPa

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