A 11.0 L balloon contains helium gas at a pressure of 625 mmHg. What is the fina

Question

A 11.0 L balloon contains helium gas at a pressure of 625 mmHg. What is the final pressure, in millimeters of mercury, of the helium gas at each of the following volumes, if there is no change in temperature and amount of gas? Part A 25.0 L, Part B 2.50 L, Part C 13300 mL, Part D 1210 mL. A 11.0 L balloon contains helium gas at a pressure of 625 mmHg. What is the final pressure, in millimeters of mercury, of the helium gas at each of the following volumes, if there is no change in temperature and amount of gas? Part A 25.0 L, Part B 2.50 L, Part C 13300 mL, Part D 1210 mL.

Explanation / Answer

vi = 11.0 L
Pi = 625 mm Hg

A)
vf = 25.0 L

use:
Pi*vi = Pf*vf
625*11.0 = Pf*25.0
Pf =275 mm Hg
Answer: 275 mm Hg

B)
vf = 2.50 L

use:
Pi*vi = Pf*vf
625*11.0 = Pf*2.50
Pf =2750 mm Hg
Answer: 2750 mm Hg

C)
vf = 13300 mL = 13.3 L

use:
Pi*vi = Pf*vf
625*11.0 = Pf*13.3
Pf =517 mm Hg
Answer: 517 mm Hg

D)
vf = 1210 mL = 1.210 L

use:
Pi*vi = Pf*vf
625*11.0 = Pf*1.210
Pf =275 mm Hg
Answer: 5682 mm Hg

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