Cancer Survival Rates: Suppose a certain type of cancer has a 0.67 survival rate

Question

Cancer Survival Rates: Suppose a certain type of cancer has a 0.67 survival rate for five years. This means that 67% of those diagnosed with this type of cancer have survived at least 5 years (those that die from something else in that time are excluded). Now, suppose you check on 120 people with this type of cancer 5 years after diagnosis and treatment from a particular hospital.

(a) Assume the 0.67 survival rate is accurate. In randomly selected groups of 120 people diagnosed with this type of cancer, what is the mean number of survivors at the five-year mark? Round your answer to one decimal place.

=

(b) What is the standard deviation? Round your answer to one decimal place.

=

(c) You check on 120 such patients from a certain hospital and find that only 67 survived (about 56%). With respect to the mean and standard deviation found in parts (a) & (b) respectively, what is the z-score for this many survivors? Round your answer to two decimal places.
z =  

(d) While the survival rate at this particular hospital is below the national average, is 67 out of 120 low enough to be considered unusual?

Yes, that is an unusual rate.No, it is not low enough to be considered unusual.

Explanation / Answer

a) = np=120*0.67=80.4

b) =(np(1-p))1/2 =5.15

c)as z score =(X-mean)/std deviation =(67-80.4)/5.15=-2.60

d) as z score is below critical value of |2| ; therefore

Yes, that is an unusual rate.

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