a blackboard.com/webapps/assessment/take/take jsp?course assessment id- 441844 1
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a blackboard.com/webapps/assessment/take/take jsp?course assessment id- 441844 18course ide 113557 18.content id- 6885004 18iquestion nu.. Question Completion Status: Moving to another question wil save this response. Question 14 of 201 Question 14 1.25 points Save Ans Catherine Chao, Director of Marketing Research, is evaluating consumer acceptance of alternative toothpaste packagos. She wonders whether acceptance is influenced by children in the household. Her staff prepared the following contingency table from a random sample of 200 households Children in Household e-teenagers teenagers none Pump 60 20 Package Tube 35 Using a significance level of 0.01, the appropriate decision is reject the null hypothesis and conclude there is no evidence of assocation between the two variables e do not reject the null hypothesis and condlude there is no evidence of association between the two variables reject the null hypothesis and conciude there is evidence of assooiation between the two vaniables e do not reject the null hypothesis and conclude there is evidence of association between the two variables Firefox Installer (1).exe 12:1 12/14 dExplanation / Answer
here applying chi square test of association on above:
p vlaue for above test statistic =0.1108
as p vlaue is greater than 0.01 level
do not reject the null hypothesis and conclude there is no association between the two variables
Observed O pre-teenagers teenagers none Total pump 60 20 35 115 tube 35 25 25 85 Total 95 45 60 200 Expected E=rowtotal*column total/grand total pre-teenagers teenagers none Total pump 54.625 25.875 34.500 115 tube 40.375 19.125 25.500 85 Total 95 45 60 200 chi square =(O-E)^2/E pre-teenagers teenagers none Total pump 0.5289 1.3339 0.0072 1.870 tube 0.7156 1.8047 0.0098 2.530 Total 1.244 3.139 0.017 4.4002Related Questions
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