A test was conducted of two overnight mail delivery services. Two samples of ide
ID: 3363414 • Letter: A
Question
A test was conducted of two overnight mail delivery services. Two samples of identical deliveries were set up so that both delivery services were notified of the need for a delivery at the same time. The hours required to make each delivery follow Do the data shown suggest a difference in the delivery times for the two services? Use a.05 level of significance for the test. Use Table 1 of Appendix B Click on the datafile logo to reference the data DATA file Delivery 24.5 26.0 28.0 21.0 18.0 36.0 25.0 21.0 24.0 26.0 31.0 28.0 25.5 32.0 20.0 9.5 28.0 29.0 22.0 23.5 29.5 30.0 10 What is the z-statistic? If required, round your answer to two decimal places. Enter negative values as negative number, if necessary What is the p-value? If required, round your answer to two decimal places Conclude: Select your answer- Observe: There -Select your answer-a significant differenceExplanation / Answer
Given that,
mean(x)=2.65
standard deviation , s.d1=0.87
number(n1)=503
y(mean)=2.82
standard deviation, s.d2 =0.83
number(n2)=1342
null, Ho: u1 = u2
alternate, H1: u1 != u2
level of significance, = 0.05
from standard normal table, two tailed t /2 =1.965
since our test is two-tailed
reject Ho, if to < -1.965 OR if to > 1.965
we use test statistic (t) = (x-y)/sqrt(s.d1^2/n1)+(s.d2^2/n2)
to =2.65-2.82/sqrt((0.7569/503)+(0.6889/1342))
to =-3.7842
| to | =3.7842
critical value
the value of |t | with min (n1-1, n2-1) i.e 502 d.f is 1.965
we got |to| = 3.78422 & | t | = 1.965
make decision
hence value of | to | > | t | and here we reject Ho
p-value: two tailed ( double the one tail ) - Ha : ( p != -3.7842 ) = 0
hence value of p0.05 > 0,here we reject Ho
ANSWERS
---------------
null, Ho: u1 = u2
alternate, H1: u1 != u2
test statistic: -3.7842
critical value: -1.965 , 1.965
decision: reject Ho
p-value: 0
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