Calculate the mean and standard error for the following sample, 32, 39, 30, 53,

Question

Calculate the mean and standard error for the following sample, 32, 39, 30, 53, 28, 30, 30, 46, 45. Is the null hypothesis of the true mean 90 true or false according to a one-tailed t-test assuming the sample's mean is greater than the null hypothesis with an alpha level of 0.05. Tip: once you enter in data for the y, use the following R comand: t.test(y.A, mu =90, alternative = alternativeoption), where alternativeoption is either two.sided, greater, or less (in quotes), depdending on the question text.

True or False?

Explanation / Answer

3.02306

Null hypothesis: the populaiton mean 90

alternative hypothesis: mean is greater than 90

test statistic is t = (sample mean- populaiton mean)/SE = (37-90)/3.02306 = -17.53

P-value is one.

so accept the null hypothesis. the populatin mean is 90

x (x-mean)^2 32 25 39 4 30 49 53 256 28 81 30 49 30 49 46 81 45 64 333 658

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