Determine the point estimate of the population proportion and the margin of erro

Question

Determine the point estimate of the population proportion and the margin of error for the given confidence interval. Lower bound: 0201. upper bound: 0.249, n - 1200 Given the sample size n = 49, population parameter a = 28 find A random sample of 1003 adults Americans was asked "Do you pretty much think televisions are a necessity or luxury you could do without ? Of 1003 adults surveyed. 521 indicated that televisions are a luxury they could do without. Construct a 95% confidence interval for the population proportion of adult American who believe that television arc a they could do without. Determine the null and alternative hypothesis

Explanation / Answer

Q1.
Margin of Error = (Upper-Lower)/2 = (0.249-0.201)/2 = 0.024
Point of estimate = Lower + Margin of Error = 0.201 + 0.024 = 0.225

Q2.
Standard Deviation= sd/ Sqrt(n)
Where,
sd = Standard Deviation
n = Sample Size

Standard deviation( sd )=28
Sample Size(n)=49
Standard Error = ( 28/ Sqrt ( 49) )
= 4

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.