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Close Window Moving to another question will save this response. Question 120121 Question 12 5 points Save Answer Three activities are candidates for crashing on a project network for a large computer installation (all are, of course, crtical), Activity details are in the following table: trvi ormal Time (days) rash Time (days) ormal Cost Total Cost with Crashing Immediate Predecessor 5,600 6.200 .200 4.200 The sequence of crashing for first two days isand the total cost of crashing for 2 days TRN-NI O a. A and C: $ 1800 O b.B and C: S 1500 O c. None of the options O d. A and B: $1500 00:188 018 1:4 :com Moving to another question will save this response

Explanation / Answer

Correct Answer:

D

Working note:

Crash cost per day for Activity A = 5600-5000 = $600

Crash cost per day for Activity B = (3000-1200)/2 = $900

Crash cost per day for Activity C = (6200-4200)/2 = $1000

Activity A has the lowest crashing cost per day, so first crashing of A will take place for 1 day. Since, crashing of activity A cannot be done for day-2, then activity B will be crashed for 1 day.

So,

Total crash time =2 day

Activity to be crashed = A & B

Total crash cost = 600 + 900 = $1500 (for 2 days)

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