What will happen when the following snippet of code is executed: li $s0, 0x10000

ID: 3585105 • Letter: W

Question

What will happen when the following snippet of code is executed:

li $s0, 0x10000014

lw $t0, 8($s0)

a. The value, 0x10000014, will be copied from $s0 into $t0.

b. The value currently in $t0 will be copied to the memory address, 0x10000014.

c. The value currently at the memory address, 0x10000014, will be copied into $t0.

d. The value currently in $t0 will be copied to the memory address, 0x10000022.

e. The value currently at the memory address, 0x10000022, will be copied into $t0.

f. The value currently in $t0 will be copied to the memory address, 0x1000001C.

g. The value currently at the memory address, 0x1000001C, will be copied into $t0.

a. The value, 0x10000014, will be copied from $s0 into $t0.

b. The value currently in $t0 will be copied to the memory address, 0x10000014.

c. The value currently at the memory address, 0x10000014, will be copied into $t0.

d. The value currently in $t0 will be copied to the memory address, 0x10000022.

e. The value currently at the memory address, 0x10000022, will be copied into $t0.

f. The value currently in $t0 will be copied to the memory address, 0x1000001C.

g. The value currently at the memory address, 0x1000001C, will be copied into $t0.

The value currently in $t0 will be copied to the memory address, 0x1000001C.

Option f is correct.

Here the implementation is always +8 so find value.

1000014 +8

Hexacdecima addition 8+4=12=c

= 100001c

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