must compile the program will read names, ages and weights for up to 100 people.

Question

must compile

the program will read names, ages and weights for up to 100 people. This means that you need 3 arrays of 100 elements each. Then it will sort the data based on decreasing weights and finally print a report.

Here is the code for a bubble sort function sorting 1 array:

void sort ( double x[], int n )
{
int i;
bool swapped;

do {
swapped = false;
for ( i = 0; i < n-1; i++ ) {
if ( x[i] > x[i+1] ) {
swap ( x[i], x[i+1] );
swapped = true;
}
}
} while ( swapped );
}





Given appropriate input data you should produce a report like this one:

Name Age Weight
----------- --- ------
Fred 35 250.5
Barney 31 165.0
Betty 28 110.5
Wilma 33 115.0

Here is your skeleton code:

#include
#include
#include

using namespace std;

const int MAX = 100;

int read_data ( string names[], int ages[], double weights[], int max )
{
int n;

//
// Write this function first.
// Below here is the loop to read the input data.
//


assert ( n > 0 && n <= MAX );
return n;
}

void sort ( string names[], int ages[], double weights[], int n )
{
assert ( n > 0 && n <= MAX );

//
// Write this function last.
// Below here is the bubble sort code.
//

}

void print_report ( string names[], int ages[], double weights[], int n )
{
assert ( n > 0 && n <= MAX );

//
// Write this function second, so you can verify that you have read the data.
// Below here is the code to print the report.
//
}

int main()
{
string names[MAX];
int ages[MAX];
double weights[MAX];
int n;

n = read_data ( names, ages, weights, MAX );
assert ( n > 0 && n <= MAX );
sort ( names, ages, weights, n );
print_report ( names, ages, weights, n );

return 0;
}

Explanation / Answer

Here. Compiled in VS 2010. I used insertion sort here. It gave me the result as u need. Check it please. U can ask me any questions concerning the code if u need. #include #include #include using namespace std; const int MAX = 100; int read_data ( string names[], int ages[], double weights[], int max ) { int n; cout > n; for (int i = 0; i

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.