Assume a 32-bit virtual address space and a 4 KB page size 1. The execution time

Question

Assume a 32-bit virtual address space and a 4 KB page size

1. The execution time for a benchmark test is 150 ?s. After a hardware improvement, the execution
time for that test is now 100 ?s. What is the overall speedup?
2. Suppose the prior improvement only helped 50% of the time but the CS guys and gals
developed a new benchmark test that used the enhanced hardware improvement 90% of the time.
a. What is the speedup of the enhancement?
b. What is the new advertised speedup based on this benchmark?

Explanation / Answer

Solution:

1)

The speedup = Execution time(old)/Execution time(new)= 150/100= 1.5

2)

a)

So effective improvement in the previous one was

0.5*100 + 0.5* 150 = 125

Now since it is improved 90% of the time

then

0.9*100 + 0.1* 150= 105

Speedup = 125/105 = 1.19047619048

b)

advertised sppedup = 150/105 = 1.42857142857

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