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Time correct answers out of20 questions. 35% percent spent on the testis 18 minu

ID: 3797256 • Letter: T

Question

Time correct answers out of20 questions. 35% percent spent on the testis 18 minutes 58seconds 1 Given Ix 2A 4, which of the following is true? 2 Which of the folowing operators are right-associatve. A, && D. (binary 4) 3 answer is correct true? Given Ix-21 which ofthe following is 4 In a switch statement, the default case must appear last among alcases. Otherwise, it would result in a complation error. A true B. false 5 What is the output ofthe folowing code (Ploase indent the stalement correcsy fist.) 9 and z System.out printhrx g and z T: A none C, K 9 and z 7. D. x 9 and y &

Explanation / Answer

1) Answer: A

Explanation:- Given |x-2| <=4

                          |x-2|<=4 or x-2 >=-4

                         So answer will be |x-2|<=4 || x-2 >=-4

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2) Answer: B

          Explanation:-

Left -associative (meaning the operations are grouped from the left), right-associative (meaning the operations are grouped from the right)        

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3) Answer:- D

Explanation:- Given |x-2| >=4

                            |x-2|>=4 or x-2 <=-4

                           So answer will be |x-2|>=4 || x-2 <=-4

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4) Anwser: B

Explanation:-

It is not necessary that default statement must appear at last.

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5) Answer: A

Explanation

Run following code, it will not print.

package chegg;

public class Demo {   

      public static void main(String[] args) {   

            int x=9;

            int y=8;

            int z=7;   

            if(x>9)

                  if(x>8)

                  System.out.println("x>9 and y> 8");

            else

                  if(z>=7)

                  System.out.println("x<=9 and z>=7 ");

                  else

                  System.out.println("x<=9 and z<=7 ");

      }

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15) Answer: B

Explanation:-

Manth,random() function Return value will be

A floating-point, pseudo-random number between 0 (inclusive) and 1 (exclusive) [0,1)

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If you have any query, please feel free to ask.

Thanks a lot.

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