A copy constructor has the same name as the class (let\'s call it (A) and has a

Question

A copy constructor has the same name as the class (let's call it (A) and has a parameter that a. Is call-by value of an A object b. Is call-by-reference of another class c. Is call-by-reference of an A class object. d. none of these A class member that is to be shared among all objects of a class is called a. a const member b. a static member c. a reference member d. a value member e. none of the above Which statement about const member function is true? a. Member functions declared const are allowed to modify the object. b. const declarations are allowed for constructors and destructors. c. Only const member functions can be called for const objects. d. none of the above Which is the correct way to use member initializer if Count is a class and x is a const data member? a. (Count(int i): i(x) {} b. Count(int i): x(i) {} c. Count(inl i) {x = i;} d. none of the above Which statement about static member function is true? a. It is a service of a specific object of the class. b. A static member function can use this pointer. c. static data members and static member functions exist independently of any objects of a class. d. none of the above 6. The assignment operator "=" operator may be used by objects of same class without overloading. a. True b. False The equality "=" operator may be used by objects of same class without overloading. a. True b. False 8. If a programmer does not supply a copy constructor for the class, then the compiler generates and executes a default one. a. True b. False 9. A const object must be initialized using the member initializer syntax only. a. True b. False

Explanation / Answer

Hello,
In question you have marked some answers so I will assume that those answers you know and I will try to answer 4 questions other than those.

1. Answer is c. Is call-by-reference of an A class object

Because copy constructor's syntax would be like this

classname (const classname &obj) {
// body of constructor
}

Here we passed the reference of the object of the same class

2. Answer is b. a static member
because static members need no object of the class to be accessed and thus one copy of the static member can be accessed across all objects of the same class thus it is shared among all objects of the class.

4. Answer is b. Count(int i):x(i){}
Because it's correct syntax to initialize constant members.

5. Answer is c. static data members and static member functions exist independently of any objects of a class.

It is correct because static data members and static member functions need to objects to be accessed, They are independent and they can be accessed using just the class name.

I hope you got all the explanation you needed.
If you have any queries or doubts then please let me know in comments.
Good luck.

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