e. if a computer with the above configuration sends a packet to 10.10.20.20, exp
ID: 3833348 • Letter: E
Question
e. if a computer with the above configuration sends a packet to 10.10.20.20, explain the routes that the paket will have to reach the destination?
f. what will happen if the same computer sends a packet to 10.200.10.20 computer? e. if a computer with the above configuration sends a packet to 10.10.20.20, explain the routes that the paket will have to reach the destination?
f. what will happen if the same computer sends a packet to 10.200.10.20 computer? Route Table Interface List 0x1 MS TCP Loopback interface 0x2 ...00 bo do 25 bf 48 3Con 3C920 Integrated Fast Ethernet Controller 3C905C-TX Compatible Packet Scheduler Miniport Active Routes Netnask Gatewa Interface Metric Network Destination 0.0.0.0 0.0.0.0 10.10.20.25 10.10.20.1 20 255.255.255.0 10.10.20.0 10.10.20.1 10.10.20.1 20 10.10.20.1 255.255.255.255 127.0.0.1 127.0.0.1 20 10.255.255.255 255.255.255.255 10.10.20.1 10.10.20.1 20 255.0.0.0 127.0.0.0 127.0.0.1 127.0.0.1 224.0.0.0 240.0.0.0 10.10.20.1 10.10.20.1 20 255.255.255.255 255.255.255.255 10.10.20.1 10.10.20.1 10.10.20.250 Default Gateway: Persistent Routes None
Explanation / Answer
Computer IP address: 10.10.20.1
Netmask of the computer: 255.255.255.255
Default gateway: 10.10.20.250
E) SInce the IP address of the computer (the packet is being sent from) is 10.10.20.1 and for this netmask is 255.255.255.255, then all IPs in the range of 10.10.20.1-10.10.20.255 will come under same route. So when packets are sent within this IP range(10.10.20.1-10.10.20.255), then the address of the destination(10.10.20.20) is found through ARP Protocol and the packet will be sent to the address.
F) Since 10.200.10.20 is not in the range of (10.10.20.1-10.10.20.255) which says IP 10.200.10.20 is not in same route as IP 10.10.20.1, then the packets will be forwarded to a default gateway(10.10.20.250) which decides further routing for that packet.
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