Question about a webassign problem I just completed. I cheated a little and used

Question

Question about a webassign problem I just completed.

I cheated a little and used the "practice another version" option to see the format. It resembled the format: .200+.143(exp(-t/.7)) where exp was the notation for e raised to some power.

It was easy enough to calculate that the maximum possible current for the right loop was e/R or 10/70000 and then to derive the current over time would be (10/70000)*(exp(-t/.7)) where .7 is the time constant I calculated earlier. I just have no idea why it is just the right loop that behaves in this manner?

Explanation / Answer

The capacitor of right loop gets charged when switch is open. As soon as switch is closed the left circket is shorted by the switch and left and right circuits get separated nd behave separately. Now what we have is R and charged C in right ciruit, therefore capacitor now discharges through R, hence behaves like RC discharging circuit.

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.