Below is a schematic representation of one VNTR studied in 20 individuals. Since

Question

Below is a schematic representation of one VNTR studied in 20 individuals. Since it is a single locus, each person should have two bands, one for each of the two homologous chromosomes. There are five different size bands (labeled A-E for convenience) seen in this sample. Assuming this small sample is representative of the population, what are the frequencies of each fragment in the population? There is a crime committed and DNA evidence shows bands A and E. A suspect is tested and found to have the same two bands. He could be the criminal, but he could also be some poor schmuck in the wrong place at the wrong time. What is the chance that a random individual from this population would have exactly those two bands? Would you convict the suspect based on this evidence?

Explanation / Answer

Frequency of A = 4/40 (4 A bands divided by total 40 bands) = 1/10 = 0.1

Frequency of B = 9/40

Frequency of C = 6/40

Frequency of D = 11/40

Frequency of E = 8/40

There is no chance of a random individual to be a criminal among these 20 people. This is so because , none of the 20 persons are having A and E bands altogether. so, none of these is the criminal.

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