Consider the following reaction: If the tale of decrease for the parta pressure

Question

Consider the following reaction: If the tale of decrease for the parta pressure of N1He in a dosed reacton vessel is 72 torr/h, what is the rate ofchange for the parsa pressure of NH, in the same vessel? Express the rate in toms per hour to two significant digits. At 140 torr/h Stont MLAnswers Give Up Correct Partial pressure is equal to the product of the total pressure and the mole fraction of a chemical species (x.) Therefore, the partial pressures can be compared based on changes to the NE, is 12, so the rate at which the partial pressure of NHa increases is twice the rate at which the partial pressure of N1He decreases. significant Figures Feedback: Your answer 144 torr/h was either rounded diferenty or used a different number of significant figures than required for this part. Part D What is the rate of change of total pressure in the vessel during the reaction? Express the rate in toms per hour to two significant digits. torr/h

Explanation / Answer

N2H4(g) + H2(g) ------- 2NH3(g)

Rate of change of pressure of NH3 = 2 * rate of change of decrease of N2H4 = 2 * 72 = 144 torr/h

Rate of decrease of H2 = Rate of decrease of N2H4 = 72 torr/h

Since the coefficient of both the reactants is equal to 1

Hence Rate of Total change of pressure = 144 torr/h - 72 torr/h - 72 torr/h = 0 torr/h

Hence the final answer will be 0 torr/h

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