Two one-cent coins were weighed on an electronic balance of high sensitivity, an

Question

Two one-cent coins were weighed on an electronic balance of high sensitivity, and a average mass per coin of 2, 4918 g was obtained from the data. How could you use an electronic balance of intermediate sensitivity to obtain an average mass contained the same number of significant figures as the value obtained high sensitivity balance? Weigh group containing more than two coins. Weigh the two-coin group but estimate the balance reading to 0.0001 g. Weigh the two-coin group two different intermediate sensitivity balances, and average the results. None of the three techniques described above will work. Explain your answer:____________________________ According to the masses recorded in Table 2.9, how do the average coin masses compare to the average coin mass determined from the slope the graph Most average masses were larger than the slope average. Most average masses were smaller than the slope average. Most average masses were about the same as the slope average. Explain your answer:__________________________ Using the difference technique, you want to accurately weigh a sample of a solid with a mass of about 0.50 g. A container is placed on a centigram balance and weighs 0.71 g. What would you set the balance to read before adding the solid to the container? 0.50 g 1.21 g 0.21 g 0.71 g Explain your answer:________________

Explanation / Answer

Q1 answer a. weigh group containing more than two coins on a low sensitivity balance will give average with higher significant figures.

Q2. Here Table 2.9 is not given in the question so this question has incomplete information and hence cannot be answered

Q3. b 1.21 g as the weight of container plus sample should add to 1.21g.

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