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Chrome File Edit View History Bookmarks People Window Help 40% Thu 4:29 PM a Lehman College CHE 168 s x C Chemistry question IChegg x www.saplinglearning.com Apps All concerns D Dashboard l Gene M WileyPLUS Sapling Learning a Valentina L.A. Wom. a The NuBra Seamless Jumeirah Inside 3. WP Online Eyeglasses. B Other Bookmarks a Attempts Score 2/18/20 11 :55 PM 1T3 /29/20 7 12:23 PM Gradebook Assignment Information Print Calculator Periodic Table Available From Not set 00 Question 3 of 3 2/18/2017 11:55 PM Due Date: Map EM Sapling Learning Points Possible: 3 Pamela atcty Universty of N work CUNY, Lehman col Grade Category: Topic 3 Homework Total (10 pts, If the Ka of a monoprotic weak acid is 5.7 x 10e, what is the DH of a 0.18 M solution of this acid? Description Policies Prac umber 2.9 You can check your answers. You can view solutions when you complete or give up on any question. You can keep trying to answer each question until you get it right or give up. There is no penalty for incorrect answers. Textbook OHelp With This Topic O Web Help & Videos Technical Support and Bug Reports O Previous Give up view salution Check Answer ONext Exi Hint

Explanation / Answer

HA = monoprotic acid

Ka = 5.7*10^-6

then

[H+] for [HA] = 0.18 M

so

weak acid ionizes:

HA <->H+ + A-

in equilbirium

Ka = [H+][A-]/[HA]

so

[H+] = x = [A-]

[HA] = M-x = 0.18-x (accouint for the dissolution)

so

Ka = [H+][A-]/[HA]

gets

5.7*10^-6= x*x/(0.18-x)

solve for x:

x = [H+] = 0.00101

pH = -log(0.00101) = 2.99

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