Compare the Total hardness results from the EDTA titration of tap water (part A)

Question

Compare the Total hardness results from the EDTA titration of tap water (part A) and the total hardness calculated based on the ion exchange column results (part 2). Should these results be equivalent? Explain why or why not. Previously, we assumed that all x^+ removed by the column were Ca^2+ ions, assuming that Na^+ and Ca^2+ were present in the water, how can you calculate the moles of Na^+ in Austin water? mmoles X^+ determined in eluate per 100ml. of eluate: _____ mmoles Ca^2+ determined in eluate per 100ml. of eluate:_____ Total mmoles X^+ per 100mL of eluate:_____ Avg mmoles Ca^2+ determined in water per 100mLof sample._____ equivalent amount expressed as X^+ per 100ml of sample:_____ mmoles as Na^+ (i.e. X^+ that is not from Ca^2+) per 100ml sample:_____ BONUS alkalinity of water samples (ppm NaHCO_3):_____ optional - Avg water alkalinity Austin, TX (Ullrich, ppm): _____

Explanation / Answer

Answer:-

Water hardness = 87 ppm

= 87 x 10-3 g/L

If Na+ is present in water then it will form NaCl salt,

So, molar mass of NaCl = 58.5 g/mol

Mass of NaCl in water= 87 x10-3 g

moles of Na+ = 87 x 10-3/58.5

= 1.49 x 10-3 mol

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