Chemistry help 1)Determine the value of the equilibrium constant, K goal, for th

ID: 494371 • Letter: C

Question

Chemistry help

1)Determine the value of the equilibrium constant, Kgoal, for the reaction

N2(g)+H2O(g)NO(g)+12N2H4(g), Kgoal=?

by making use of the following information:

2)Determine the equilibrium constant, Kgoal, for the reaction

4PCl5(g)P4(s)+10Cl2(g), Kgoal=?

by making use of the following information:

P4(s)+6Cl2(g)4PCl3(g), K1=2.00×1019

PCl5(g)PCl3(g)+Cl2(g), K2=1.13×102

Express your answer numerically.

1. N2(g)+O2(g)2NO(g), K1 = 4.10×1031 2. N2(g)+2H2(g)N2H4(g), K2 = 7.40×1026 3. 2H2O(g)2H2(g)+O2(g), K3 = 1.06×1010

1) Calculating Kgoal for the given reacton,

Divide equation (1) by 2,

Divide equation (2) by 2,

Divide equation (3) by 2,

Add them together,

1. 1/2N2 + 1/2O2 <==> NO K1 = sq.rt.(4.10 x 10^-31) = 6.40 x 10^16

2. 1/2N2 + H2 <==> 1/2N2O4 K2 = sq.rt.(7.40 x 10^-26) = 2.72 x 10^-13

3. H2O <==> H2 + 1/2O2 K3 = sq.rt.(1.06 x 10^-10) = 1.03 x 10^-5

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N2(g) + H2O(g) <==> NO(g) + 1/2N2O4(g) Kgoal = K1 x K2 x K3 = 0.179

2) Calculating Kgoal for the given reacton,

Invert the first equation,

multiply the second equation with 4

Add them together,

4PCl3 <==> P4 + 6Cl2 K1 = 1/2 x 10^19 = 5 x 10^-20

4PCl5 <==> 4PCl3 + 4Cl2 K2 = (1.13 x 10^-2)^4 = 1.63 x 10^-8

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4PCl5(g) <==> P4(s) + 10Cl2(g) Kgoal = K1 x K2 = 8.15 x 10^-28

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