In this exercise the amount of calcium carbonate (CaCO_3) in both an antacid tab

Question

In this exercise the amount of calcium carbonate (CaCO_3) in both an antacid tablet, and an unknown sample must be determined and reported. The chemical analysis method used will be a titration of Ca^2+ with the titrant EDTA. EDTA is a ligand that will from a complex ion with Ca^2+. EBT is a dye that will be used to indicate the equivalence point of the titration. EBT is also a ligand, and therefore will form a different complex ion with Ca^2+ than that of EDTA In solution the two ligands, EDTA and EBT, compete for the Ca^2+ ion. EBT has the property that when it is bonded to Ca^2+ it forms a RED complex. When it is not bonded to Ca^2+ (or is free from Ca^2+) it is BLUE in color. As EDTA is added to the dissolved CaCO_3 solution, Ca^2+ ions will break the bonds they have initially formed with the EBT dye and make new bonds with the EDTA to form a more stable complex. This process "frees up" EBT molecules in the solution. Each molecule of EDTA makes _____ coordinate covalent bonds to one Ca^2+ cation. Enter an integer as an answer. Do not include units.

Explanation / Answer

Answer:-

Each molecule of EDTA makes 6  coordinate covalent bonds to one Ca2+ cation because EDTA is a hexadentate ligand and it forms octaheral complex with the Ca2+ cation.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.