Consider two systems A and B each having 4 distinguishable particles and only 2

Question

Consider two systems A and B each having 4 distinguishable particles and only 2 energy levels (0 & 1). Initially, system A has 2 particles in the exited state (0011), while system B has 3 (0111). What are the multiplicities (ohm(E_A) and ohm(E_B) of the isolated systems A and Bin this state? Let's bring the two systems into thermal contact so they can exchange energy (while the total energy is not changed). Calculate the multiplicity of the overall system (ohm_AB). Based on the maximum multiplicity (entropy) principle, what will be the direction of heat flow (from A to B, or back), if any?

Explanation / Answer

According to two systems A nd B , A has 2 particles in the excited state means multiplicity of the system is 2 and fo ror system B is 3 multiplicity .

Multiplicity : The multiplicity of the energy level defined as 2S+1 Where, S is the total spin angular momentum. States with the multiplicity.1,2,3,4 .... this is the spectrochemical aspects.

S angular momentum means which describes the orientation of the electrons in the space.

so 2S+ 1 , S = 1/2

so multiplicity is 2

and the orientation of these two electrons is clock wise .

When the sytems are in thermal contact they can exchange energy.

the over all multiplicity is 5 .

Based on the maximum multiplicity principle rule : energy is flowing from lower entropy to higher so heat flow will occure from A to B. In A system 2 multiplicity and B having 3 .

Entropy : degree of randomness.

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