5.1 Problem numbers in red indicate that the solution to the problem is given in

Question

5.1

Problem numbers in red indicate that the solution to the problem is given in the Student's Solutions Manual. Consider the formation of glucose from carbon dioxide and water (i.e., the reaction of the photosynthetic process): 6CO_2 (g) + 6H_2 O(l) rightarrow C_6 H_12 O_6 (s) + 6O_2 (g). The following table of information will be useful in working this problem: Calculate the entropy and enthalpy changes for this chemical system at T = 298 K and T = 310. K. Calculate also the entropy change of the surroundings and the universe at both temperatures, assuming that the system and surroundings are at the same temperature. The Chalk Point, Maryland, generating station

Explanation / Answer

1. Use the entropy values in the table.

S° = S° product - S° reactant

S° = [ (209.2 J/mol k) + 6(205.2 J/mol k) ] - [ 6(213.8 J/mol K) + 6(70.0 J/mol K) ]

S° = -262.4 J/mol.K

2. use the enthalpy value from table :

H° = H° product - H° reactant

H° = [(-1273.1 KJ/mol) + 6(0.0 ) ] - [ 6(-393.5 Kj/mol) + 6(-285.8 KJ/mol) ]

H° = 2802.7 KJ/mol

3. Go = H° - TS°

S° surrounding = -H°/T = -q/T

S°total = S° surr + S°sys   

G° at 298 K

G° = 2802700 J/mol - 298 K (-262.4 J/mol k)

G° = 2880895.2 J/mol  

G° at 310 K

G° =  2802700 J/mol - 310 K (-262.4 J/mol k)

G° = 2884044 J/mol

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