Consider a chromium - silver voltaic cell that is constructed such that one half

Question

Consider a chromium - silver voltaic cell that is constructed such that one half - cell consists of the chromium. Cr electrode immersed in a Cr(NO_3)_3 solution. And the other half the two electrodes are by a copper wire. The Cr electrode act as the anode. And the Ag electrode acts as the cathode. To maintain separating the two half-cells. Use this information to solve parts B, C, and D. The half-cell is a chamber in the voltaic cell where one half-cell is the site of the oxidation reaction and the other half-cell is the site of the reduction reaction. Type the reaction that takes place at the anode for the chromium-silver voltaic cell. Indicate the physical states using the abbreviation (s), (l) or (g) for solid liquid or gas solution. Do not forget to add electrons in your reaction. Express your answer as a chemical equation.

Explanation / Answer

When chromium electrode and silver electrode are connected ., chrlomium under goes oxidation and silver gets reduced.

SRP of Cr = -0.74V and SRP of Ag is =+0.80V

Thus the reaction at anode (oxidation) is

Cr(s) ----------> Cr+3 (aq) + 3e-

The reaction at cathode (reduction ) is

Ag+ (aq) +e- -------> Ag(s)

Net cell reaction is

3Ag+(aq) + Cr (s) ------> 3Ag (s) + Cr+3(aq)

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