What would be the mass of 4.64 times 10^24 molecules of NO_3 gas? How many molec

Question

What would be the mass of 4.64 times 10^24 molecules of NO_3 gas? How many molecules of PBr_5 are in 65.0 g PBr_5? H_2SO_4 + K rightarrow k_2SO_4 + H_2 How many grams of K will complete the reaction with 56.6 g H_2SO_4? If we start with 39.54 g K and react it with an excess of H_2SO_4, What would be the volume of the hydrogen produced at STP? Using the data in #4, How many molecules of the potassium sulfate will be produced? MoCl_5(aq) + AgNO_3(aq) rightarrow AgCl + M_0(NO_3) If we begin with 46.43 g MoCl_5, how many grams of AgNO_3 will be needed to complete the reaction. Using the data from #6 what would be the mass of the precipitate produced from this reaction? Using the data from #6 again tell how many formula units of the product that remains aqueous would be produced in this reaction. C_4H_10O_2 + O_2 rightarrow CO_2 + H_2O If we completely react 74.6 g C_4H_10O_2, how many liters of O_2 gas (at STP would complete the reaction?

Explanation / Answer

How many moles of PbR5 are in 65g PBr5

Molar mass of PBr5 = 430.493761 g/mol

Molecular weight calculation:
30.973761 + 79.904*5

65g PBr5 =0.1509 moles ------------answer

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What would be mass of 4.64 x10^24 molecules of NO3 gas

Number of moles =4.64 x10^24 /6.023 x10^23=7.70 moles

NO3(gas) is 62.0049 g/mol.

= 62.0049 g/mol. *7.70 moles=477.43 grams

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