Calculate the propagated error ( of both the standard molar energy change and st

Question

Calculate the propagated error ( of both the standard molar energy change and standard molar enthalpy change. What was the largest contributing factor for the error in each (quantitatively)? Circle a specific variable as the largest contributing factor for error in each.

standard molar energy change (trial 1) = -6564.463769 kJ/mol                                  standard molar energy change (trial 2) = -6460.14863 kj/mol

standard molar enthalphy change (trial 1) = -6565.703253 kJ/mol                              standard molar enthalphy change (trial 2) = -6461.388114 kJ/mol

molar energy change (trial 1)= -33.48 kJ/mol                                                                mollar energy change (trial 2) = -33.48 kJ/mol

Explanation / Answer

standard molar energy change average = (-6564.463769 + -6460.14863)/2 = -6512.306 kJ/mol

molar enthlpy change average= 6513.545 kJ/mol

molar energy change average = -33.48 kJ/mol

in case of molar energy change error = 0

for standard molar energy change

error in trial 1 = (6512.306 - 6564.463769)/ 6512.306 * 100 = 0.8 %

error in trial 2 = (6512.306 - 6460.14863)/ 6512.306 * 100 = 0.8 %

for standard molar enthalpy change

error in trial 1= (6513.545 - 6565.703253)/ 6513.545 * 100 = 0.80 %

error in trial 2= (6513.545 - 6461.388114)/ 6513.545 * 100 = 0.80 %

In all the trials errors are same for both cases.

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