What would happen if you carried out a TLC separation of acetaminophen and phena

Question

What would happen if you carried out a TLC separation of acetaminophen and phenacetin in a normal phase and reverse phase TLC system? Explain which should have a higher Rf value for ea type of chromatography and explain why. ch 7. Describe the effects on your experimental outcomes from the following situations: 1) You allowed the TLC to develop too long and the solvent ran off the plate. 2) The TA helping with lab used ammonia instead of acetic acid in your developing solvent. 3) You marked the starting line with a ballpoint pen. 1) 2) 3)

Explanation / Answer

ANS:

6).The TLC mainly reflects the Rf value of solute based on their solubility in the mobile phase which is related to polarity of the solute

In non polar solvent , Phenacetin would have a higher Rf ( retenion) value due to more polar nature than acetaminophen which is polar due to presence of hydroxyl group in it. We all know that "like dissolves like". Nonpolar molecules would be attracted more to the non-polar solvent, making it move faster along TLC plate, which would give them higher Rf values.

However in poalr solvent the Rf value ot acetaminophen will be high due to the same reason

7.

1) We would not be able to calculate Rf value as Rf value is defined as ratio of distance travelled by compound and distance travelled by solvent front ( which in this case is not clear)

2) Acetic acid being more polar will affect the Rf value as mentioned in part A

3) the ball point pen contains ink which als act as solute and will move alongwith the studied solute and due to theier colour will make our results ambiguous.

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