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Molecular Biology help ASAP! Answer conceptual question 1,2,3,4. What is the p a

ID: 55405 • Letter: M

Question

Molecular Biology help ASAP! Answer conceptual question 1,2,3,4. What is the p at Conceptual Questions methods for labeling molecules and then visualizing their location have been presented. Many Fill in the following table to ensure you understand each of these labeling methods la- What molecule does it tag? Where does it bind? tin How do you Label Ethidium Bromide Radioisotope Fluorescence Biotin Digoxigenin 2 Interpret the following zoo blots Does the DNA probe identified in each gel belong to a non-coding region of DNA or a coding region of DNA? oB. C. Probe is fronm Probe is from humans Probe is from Drosophila

Explanation / Answer

1.Ethidium bromide: It tags DNA, it binds to the major grroves of the DNA and visualized using ultraviolet light.

Radioiostope: Tags both DNA and aminoacids in proteins, replaced with normal base of DNA or aminoacid of the protein and can be counted using geiger counter which counts the radiation.

Fluorescence: Usually proteins are tagged, it binds directly to the protein and visulaised by exciting with ultraviolet light so that, it emits light in the visible region.

Biotin: Proteins are tagged with this molecule, binds to the indivdual aminoacids, these biotin labelled proteins can be separated using streptavidin affinity chromatography.

Digoxigenin: Conjugated into proteins and nucleotides, binds to triphospahe group in nucleotides, detected using anti digoxigenin antibodies in ELISA.

2. A. The probe is from coding region of paramecium, thats why it is binding only to paramecium.

B. The probe is non coding region of humans, all primates will have near to similar non coding regions.

C. The probe is non coding region of drosophila, the probe is binding to all insect species but not the mouse.

3. The father is genetic father only to the child 1 beacuse in both the gels, atleast one probe is similar in child 1 and father. In child 2 none of probe from father is binding but only probe from mother is binding.

So only Child 1 will have the father has genetic father but not child 2

4. A. 6 fragments will form from the circularised DNA, 7 fragments in linearised DNA

B. I am not able to draw it here, you can calculate using the size of the framents as given above.

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