For the following reaction: C4H8(g) + 602(g) 4CO2(g) + 4H20(1) Compound Hof (k m

Question

For the following reaction: C4H8(g) + 602(g) 4CO2(g) + 4H20(1) Compound Hof (k mol-1) S(J mol-1 K-1) C4He (9)-17.90 02 (9)0.00 CO2 (9) -393.51 H20 ) 293.60 205.70 213.74 69.91 2 285.83 Calculate G (in kJ) at 300.19 K for this reaction. Report your answer to two decimal places in standard notation (i.e. 123.45 k). Assume H, and So do not vary as a function of temperature. 2581 kJjmol Submit Answer Incompatible units. No conversion found between "k/mol" and the required units.Tries 0/3 Previous Tries

Explanation / Answer

Given:
Hof(C4H8(g)) = -17.9 KJ/mol
Hof(O2(g)) = 0.0 KJ/mol
Hof(CO2(g)) = -393.51 KJ/mol
Hof(H2O(l)) = -285.83 KJ/mol

Balanced chemical equation is:
C4H8(g) + 6 O2(g) ---> 4 CO2(g) + 4 H2O(l)

Ho rxn = 4*Hof(CO2(g)) + 4*Hof(H2O(l)) - 1*Hof( C4H8(g)) - 6*Hof(O2(g))
Ho rxn = 4*(-393.51) + 4*(-285.83) - 1*(-17.9) - 6*(0.0)
Ho rxn = -2699.46 KJ

Given:
Sof(C4H8(g)) = 293.6 J/mol.K
Sof(O2(g)) = 205.7 J/mol.K
Sof(CO2(g)) = 213.74 J/mol.K
Sof(H2O(l)) = 69.91 J/mol.K

Balanced chemical equation is:
C4H8(g) + 6 O2(g) ---> 4 CO2(g) + 4 H2O(l)

So rxn = 4*Sof(CO2(g)) + 4*Sof(H2O(l)) - 1*Sof( C4H8(g)) - 6*Sof(O2(g))
So rxn = 4*(213.74) + 4*(69.91) - 1*(293.6) - 6*(205.7)
So rxn = -393.2 J/K

Ho = -2699.46 KJ/mol
So = -393.2 J/mol.K
= -0.3932 KJ/mol.K
T = 300.19 K

use:
Go = Ho - T*So
Go = -2699.46 - 300.19 * -0.3932
Go = -2581.42 KJ/mol
Answer: -2581.42 KJ/mol

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