For the following reaction: C5H12(I) + 802(g) rightarrow 5CO2(g) + 6H2O(I) Calcu

Question

For the following reaction: C5H12(I) + 802(g) rightarrow 5CO2(g) + 6H2O(I) Calculate Delta H degree rx (in kJ) for this reaction. Report your answer to two decimal places in standard notation {i.e. 123.45 kJ). Calculate Delta S degree rx (in J/K) for this reaction. Report your answer to two decimal places in standard notation (i.e. 123.45 J/K). Calculate Delta G degree rx (in kJ) at 769.52 K for this reaction. Report your answer to two decimal places in standard notation (i.e. 123.45 kJ). Assume Delta H degree f and S degree do not vary as a function of temperature. Is this reaction spontaneous or not spontaneous at the temperature given in part 3?

Explanation / Answer

1. -505.84 KJ/mol

2. -185.52 J/mol K

3. delta G = -505.84 + (769.52*185.52)/1000 KJ/mol = -363.08 KJ/mol

4. non spontaneous at: 505.84*1000/185.52 K = 2726 K

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